我无法使用自己发布的rest数据服务，然后用超图自带的example SQL查询 rest数据服务是可以的，但是就算是超图的 我用console(sqlParam); console( resultLayer);查看属性，F12报错，说是sqlParam没有被定义？ Uncaught ReferenceError: sqlParam is not defined
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>数据集SQL查询</title>
</head>
<body style=" margin: 0;overflow: hidden;background: #fff;width: 100%;height:100%;position: absolute;top: 0;">
<div id="map" style="margin:0 auto;width: 100%;height: 100%"></div>
<script type="text/javascript" src="dist/include-leaflet.js"></script>
<script type="text/javascript">
var host = window.isLocal ? window.server : "http://support.supermap.com.cn:8090";
var map, resultLayer,
baseUrl = host + "/iserver/services/map-world/rest/maps/World",
url = host + "/iserver/services/data-world/rest/data";
map = L.map('map', {
preferCanvas: true,
crs: L.CRS.EPSG4326,
center: {lon: 0, lat: 0},
maxZoom: 18,
zoom: 1
});
L.supermap.tiledMapLayer(baseUrl).addTo(map);
query();
function query() {
var sqlParam = new SuperMap.GetFeaturesBySQLParameters({
queryParameter: {
name: "Countries@World",
attributeFilter: "SMID = 247"
},
datasetNames: ["World:Countries"]
});
L.supermap
.featureService(url)
.getFeaturesBySQL(sqlParam, function (serviceResult) {
resultLayer = L.geoJSON(serviceResult.result.features).addTo(map).bindPopup('SMID = 247');
});
};
console(sqlParam);
console( resultLayer);
</script>
</body>
</html>
